What is the slope of a trend line that passes through the points (5, 80) and (7, 65)?
Negative StartFraction 15 Over 2 EndFraction
Negative StartFraction 2 Over 15 EndFraction
StartFraction 2 Over 15 EndFraction
StartFraction 15 Over 2 EndFraction

-15/2 or -7.5 or -7½

Negative StartFraction 15 Over 2 EndFraction

Step-by-step explanation:

Slope or gradient of a line is the ratio of change in y co-ordinates to the change in x co-ordinates.

Therefore;

M=∆y÷∆x

The change in y co-ordinates is given by

∆y=y2-y1

Similarly, change in x co-ordinates is given by

∆x=x2-x1

Given the two points as (5, 80) and (7, 65)

X1=5 Y1=80

X2=7 Y2=65

∆y=65-80=-15

∆x=7-5=2

Hence ∆y÷∆x will be -15÷2=-7.5 or -7½

Negative StartFraction 15 Over 2 EndFraction

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)