What are the solution of a quadratic equation 49x^2 = 9

x = ±3/7

Step-by-step explanation:

49 x^2 = 9

Divide each side by 49

49/49  x^2 = 9/49

x^2 = 9/49

Take the square root of each side

sqrt(x^2) = ±sqrt(9/49)

We know  sqrt(a/b) =sqrt(a)/sqrt(b)

x = ±sqrt(9)/ sqrt(49)

x = ±3/7

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source