A rectangular field is
three times as long as it is wide. If the perimeter of the field is
200 yards, what are the field's dimensions?(length and width)

The field is 75 yards times 25 yards

L = 75 yards,

W = 25 yards

Step-by-step explanation:

What we know of the field dimensions is the following:

1) If we name the field width "W", its length is three times that: L = 3 W

2) The field's perimeter is 200 yards. That is the addition of its 4 sides (2 widths and 2 lengths). Then: 2 W + 2 L = 200 yards

SO we basically have two unknowns: "W" and "L", and two linear equations that combine the unknowns, so we can use substitution to replace the length"L" in the second equation by the equivalent expression for the length we got with the first equation (L = 3 W):

Based on this result, we find the length ofthe field using the substitution equation:

L= 3 W = 3 * 25 yards = 75 yards

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.