5 barrels catch rainwater in the schoolyard. Four barrels are the same size, and the fifth barrel holds 10 liters of water. Combined, the 5 barrels can hold at least 200 liters of water. Write an inequality whose solution is the possible size of each of the 4 barrels.

How are these two problems similar? How are they different?

The volume each of the four barrels of the same size will be at least 47.5 liters.

Step-by-step explanation:

Let the volume of each of the four barrels is v liters.

Now, the amount of water that can be held in the fifth barrel is 10 liters. The total capacity of holding water for the 5 barrels combines is at least 200 liters.

So, from the above-given information, we can write the inequality to determine the volume of each of the four barrels will be  

10 + 4v ≥ 200

Solving this we get,

4v ≥ 190

⇒ v ≥ 47.5

Therefore, the volume each of the four barrels of the same size will be at least 47.5 liters. (Answer)

for the points! : )

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3