The population of a town grows exponentially. after 1 year, the population is 34,560. after 2 years, the population is 37,325. provide an equation that can be used to predict, y, the number of people living in the town after x years. (round population values to the nearest whole number.)

Equation will be

Step-by-step explanation:

Since population of a town grows exponentially so the function to represent the population growth will be

n = number of years

where = population after n years

= population in the base year or population at 0 year

r = common ratio or the growth with which population is increasing year by year

Now It is given in the question after 1 year, the population is 34560

So the expression will be ------(1)

again question states that after 2 years, the population is 37325

The expression becomes ------(2)

Now we divide equation 2 from equation 1

r = 1.08

Now we put the value of "r" in equation 1 to calculate the value of

If y be the number of people living in the town after x years then the function formed will be

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.