What’s the differential equation of

dy/dx = y^2 (6-2x)

With initial condition that when x=3, y=1/4

Step-by-step explanation:

We have given,

and initial condition

Now,

Rearranging the variables, we get

Applying integration both sides, we get

⇒

⇒                  

Putting the initial condition (i.e., ), we get

⇒

⇒

∴

We have,      

now putting the value of in above equation, we get

⇒

⇒