Use the drip-down menus to complete the statements. A zero can be found between input values of blank because blank one zero of the function is approximately blank

A zero can be found between input values of   x = - 1 and x = 0      because one zero of the function is approximately   - 0.5     .

Explanation:

The first pictured attached contains the table with the data for this question.

The input values are the values of x.

Since the function, f(x), changes sign between x = - 1 (y = - 0.5) and x = 0 (y = 2.5), if you assume the function is continuous, you can assert that the graph of the function crosses the x-axis between those two values.

The x-coordinate where the graph crosses the x-axis is a zero of the function.

Then, you can assert that there is a zero between the input values of - 1 and 0.

That zero is approximately - 0.5. This is, the function crosses the x-axis approximately at x = - 0.5.

The second picture skecthes a graph showing the given points where you can see that the dotted curve crosses the x-axis close to x = - 0.5.

The price decreased by 40 percent㏒㏒㏒㏒㏒㏒㏒㏒㏒㏒㏒㏒㏒∞㏒∞㏑⊕⊆⊂ф

Skew lines(segments) are lines(segments) in 3 dimensions that do not intersect the given segment and are not parallel to it.  ae, bf, eg, and fh are your skew segments.  i hope that : )