Evaluating integral by net area

The graph of is a horizontal line. So the area under on [0, 8] is equal to the area of a rectangle with length 8 and height 2, or 16.

The graph of is the upper half of a circle with radius . It's symmetric about , so on the interval [0, 8], we're considering a quarter of the circle. The area of such a sector is .

Then use the fact that the definite integral is distributive over sums, meaning

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.