Select the correct answer.
Find the intersection point for the following linear functions.
Fx) = 2x + 3
g(x) = -4x - 27
A. (5,13)
B. (-5,7)
C. (-5,-10)
D. (5,-7)

(-5, -7)

Step-by-step explanation:

The intersection of f(x) and g(x) occurs when f(x) = g(x).

f(x) = g(x)

2x + 3 = -4x - 27

2x + 30 = -4x                          add 27 to both sides

30 = -6x                                  subtract 2x from both sides

-5 = x                                       divide both sides by -6

Thus, f(x) and g(x) intersect at x = -5. Plugging that into f(x) and g(x),

f(-5) = 2(-5) + 3 = -10 + 3 = -7

g(-5) = -4(-5) - 27 = 20 - 27 = -7

Thus, f(x) and g(x) intersect at (-5, -7).

A. (5, 13) i literally just got done answering that Q.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

happy to

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