Mathematics
Mathematics, 08.04.2020 06:19, veritoburito

In a cyclic quadrilateral ABCD, AD is parallel to BC. The bisector
of <BAD meets BC at E and the circle at F. Prove that:
EF=FC ( BF - DF

answer
Answers: 2

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In a cyclic quadrilateral ABCD, AD is parallel to BC. The bisector
of <BAD meets BC at E and...

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