X + a =yb solve for y

Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?

Asap i need it now choose all the answers that apply. sex-linked disorders affect males more than females affect females more than males can be carried by females, without being expressed are always expressed in males are caused by genes carried on the x and y chromosomes

The distributive property allows you to say that 3(x − 1) = 3x −