Suppose that X is the number of successes in an experiment with 9 independent trials where the probability of success is 2 5 . Find each of the following probabilities. Round answers to the nearest ten-thousandth.

Step-by-step explanation:

The complete is question is as follows

Suppose that X is the number of successes in an experiment with 9 independent trials where the probability of success is 2/5 . Find each of the following probabilities. Round answers to the nearest ten-thousandth.  

P (X < 2)

P(X ≥ 2)

Recall that given an event A, we have the following property . Note that if we consider the event A to be "X<2", its complement is the event "X≥ 2" then, the second probability is

P(X≥ 2) = 1- P(X<2). Therefore, we only need to calculate the first probability to solve the problem.

REcall that given a number of indepent trials of an experiment whose outcomes are "success" or "fail", where the probability of having a succes is p, the number of success is a random variable that is distributed as a binomial random variable. Therefore, we have that if X is the number of successes,

.

In our case, we have that p=2/5 and n=9. Hence,

Then, P(X≥ 2) = 1-0.071 = 0.929

the answer is vanilla

step-by-step explanation:

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