A farmer wishes to enclose a rectangular pasture with 1200 ft of fence. He needs to divide this rectangle into two smaller rectangles by running a fence down the middle of it parallel to the other two sides. He has 1200 ft of fence with which to do this. Find the maximum total area of the enclosure

Step-by-step explanation:

Given

total of 1200 ft of fence is available

Suppose rectangular pasture has following dimension as shown in figure.

total perimeter

Area of rectangle is

For maximum area, differentiate A w.r.t b

so

so area is

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

im not sure of the names, but the answer is 48