Find the general form of the equation for the quadratic that passes through the points (2,5) and (4,10)

The answer to your question is  5x - 2y = 0

Step-by-step explanation:

Data

A (2, 5)

B (4, 10)

Process

1.- Determina the slope of the line

slope = m = (y2 - y1)  / (x2 - x1)

   x1 = 2   y1 = 5   x2 = 4  y2 = 10

-Substitution

            m = (10 - 5) / (4 - 2)

-Simplification

            m = 5/2

2.- Find the equation of the line in the general form

            y - y1 = m(x - x1)

-Substitution

            y - 5 = 5/2(x - 2)

-Simplification

           2(y - 5) = 5(x - 2)

           2y - 10 = 5x - 10

           5x - 2y - 10 + 10 = 0

-Result

           5x - 2y = 0

answer:   14

step-by-step explanation:          

pu you stank bo u ugly bo lol

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25