The lumen output was determined for each of I = 3 different brands of lightbulbs having the same wattage, with J = 9 bulbs of each brand tested. The sums of squares were computed as SSE = 4778.7 and SSTr = 599.8. State the hypotheses of interest (including word definitions of parameters). μi = sample average lumen output for brand i bulbs

P-value > 0.100

Step-by-step explanation:

Degree of freedom Group = df1 = I - 1 = 3 - 1 = 2

Degree of freedom Error = df2 = I * (J - 1) = 3 * (9 - 1) = 24

MSTR = SSTR / df1 = 594.8 / 2 = 297.4

MSE = SSE / df2 = 4777.8 / 24 = 199.075

F = MSTR / MSE = 297.4 / 199.075 = 1.49

Using R command,  

> 1 - pf(1.49, 2, 24)

[1] 0.2454887

P-value = 0.2455

check the attatchment for better understanding

b. hoped i'm right lol

step-by-step explanation: