XYZ distribution center receives 1,000 deliveries each day. Arrivals are on time if they are within plus or minus 10 minutes of the targeted arrival. In order to have only 3.4 late or early arrivals per million deliveries (6 sigma), what would the standard deviation of arrival times need to be?A) 3.33 minutes
B) 0.83 minutes
C) 1.67 minutes
D) 6.67 minutes

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}

here is a big fat

answer: 5 17/33 % (to the tenth)

step-by-step explanation:

he guessed: 34.5 pounds

actual weight is 32.7

there for he is off:

34.5 -32.7 = 1.8

32.7 is the 100%

1.8 represents %? of 32.7

therefore:

32.7   - 100%

1.8     -     x%

x= 1.8*100%/32.7% = 18*100%/327%

x=1800%/327%   = (5 165/327)%

to the tenth:

5 17/33 %

answer is  

a.

16.1

hope you got it chief.