You have a bag of marbles with 10 green marbles and 12 black marbles. What is the probability that you pick a black marble on the first try. Do not replace that marble and pick a green marble on the second try?

6/11 and 10/21

Step-by-step explanation:

A bag of marbles has 10 green marbles and 12 black marbles. The probability of picking a black marble on the first try will be:

Green marbles= 10

Black marbles= 12

Total marbles= 12+10 = 22

Probability of picking a black marble = 12/22 = 6/11

If the marble is not replace, the probability of picking a green marble on the second try will be:

Green marbles= 10

Black marbles= 12-1= 11

Total marbles= 10+11= 21

Probability of picking a green marble= 10/21

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.