According to a candy company, packages of a certain candy contain 1616% orange candies. Suppose we examine 100100 random candies. a. What value should we expect for our sample percentage of orange candies? b. What is the standard error? c. Use your answers to fill in the blanks below. We expect % orange candies, give or take %.

a) By the Central Limit Theorem, 16%.

b) 0.0367 = 3.67%

c) We expect 16% orange candies, give or take 3.67%.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For samples of size n of a proportion p, the expected sample percentage is p and the standard error is

In this problem, we have that:

a. What value should we expect for our sample percentage of orange candies?

By the Central Limit Theorem, 16%.

b. What is the standard error?

0.0367 = 3.67%

c. Use your answers to fill in the blanks below. We expect ____% orange candies, give or take _____%.

We expect 16% orange candies, give or take 3.67%.

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i

15 batches are the most you can make

step-by-step explanation: