A park in a subdivision is triangular shaped. Two adjacent sides of the park are 503 feet and 516 feet. The angle between the sides is 38 degrees. To the nearest unit, what is the area of the park in square yards? 17,755 26,632 8,877 11,363

Area = 8,877 yd2

Step-by-step explanation:

To find the area of the park, first we need to find the length of the third side.

To find it, we can use the law of cosines:

a^2 = b^2 + c^2 − 2*b*c*cos(A)

where a, b and c are sides of the triangle, and A is the vertix between the sides b and c.

So, with b = 503 and c = 516, we have that:

a^2 = 503^2 + 516^2 - 2*503*516*cos(38) = 110211.77

a = 331.98

Now we can use the Heron's formula to calculate the area of a scalene triangle (three different sides):

Area = sqrt[s*(s - a)*(s - b)*(s - c)]

where s is the half-perimeter of the triangle.

Calculating s, we have:

s = (a + b + c) / 2 = 675.49

Then, we find the area:

Area = sqrt[675.49*(675.49 - 331.98)*(675.49 - 503)*(675.49 - 516)] = 79896.52 ft2

Converting from square feet to square yards (1 ft2 = 1/9 yd2), we have:

Area = 79896.52/9 = 8877.39 yd2

true? is that what you're asking or do you mean something else?

answer: 2530

hope this