Let F(x)= ln(t)dt. What is F'(x)?

9x²ln(x)

Step-by-step explanation:

Integral of ln(t) with respect to t is:

t×ln(t) - t

Upper limit- lower limit:

x³×ln(x³) - x³ - 0

Note: ln(x³) = 3ln(x)

F(x) = x³ × 3ln(x) - x³

F(x) = 3x³ln(x) - x³ = x³(3ln(x) - 1)

F'(x) = 3x²(3ln(x) - 1) + x³(3/x)

= 3x²(3ln(x) - 1) + 3x²

= 3x²(3ln(x) - 1 + 1)

F'(x) = 9x²ln(x)

exactly you go it

step-by-step explanation:

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry