The function h(t)=16t^+40t models the height in feet of a ball t seconds after it is thrown into the air. What is the maximum height the ball reaches after it is thrown?

The maximum height is 25 feet

Step-by-step explanation:

The correct question is

The function h(t)=-16t^2+40t models the height in feet of a ball t seconds after it is thrown into the air. What is the maximum height the ball reaches after it is thrown?

we have

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The y-coordinate of the vertex represent the maximum height that the ball reaches

Convert the quadratic equation in vertex form

Factor -16

simplify

Complete the square

Rewrite as perfect squares

The vertex is the point (1.25,25)

therefore

The maximum height is 25 feet

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step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it