A rancher wants to fence in a rectangular area of 24600 square feet in a field and then divide the region in half with a fence down the middle parallel to one side. What is the smallest length of fencing that will be required to do this?

120 ft of fencing

Step-by-step explanation:

24600 = xy

Fence (F) = 3x + 2y

24600/y  = x

F = 3(24600/y) + 2y

F = 73800/y + 2y

dF/dy = -73800/y^2 + 2

2 = -73800/y^2

y^2 = -73800/2 = 36900

y = 30

24600 = x(30)

24600 / 30 = x = 20

total fencing = 3(20) + 2(30) = (60+60) = 120

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7