JKL has vertices J(3, -5) K(-8, -1) and L(5,1). JKL will be reflected across the line y= -1 to form J'K'L'. Which quadrant will NOT contain a vertex of J'K'L'

The correct answer is second quadrant.

Step-by-step explanation:

Vertices of J ≡ (3 , -5) which shows J is in fourth quadrant. When J is reflected across the line y = -1, the point J moves to first quadrant as J' with coordinates (3 , 3).

Vertices of K ≡ (-8 , -1) which shows K is in third quadrant. When K is reflected across the line y = -1, the point K remains where it is (in the third quadrant) as it is on the line y = -1 only.

Vertices of L ≡ (5 , 1) which shows L is in first quadrant. When L is reflected across the line y = -1, the point L moves to fourth quadrant as L' with coordinates (5 , -3).

Thus each of the first, fourth and third quadrant contains a vertex except the second quadrant.

r and t.

both are 64 degrees.

i think the answer is b