Suppose that lithium calculator battery with a charge of 3 volts, actually has a voltage with uniform distribution between 2.93 and 3.1 volts. What are the expected voltage and standard deviation of voltage? What is the probability that a battery has a voltage less than 2.98?

a. E(X) = 2.413, STDEV(X)= 0.0024, P (X ≤ 2.98) = 0.3342
b. E(X) = 3.015, STDEV(X)= 0.049, P (X ≤ 2.98) = 0.2941
c. E(X) = 3.015, STDEV(X)= 0.0049, P (X ≤ 2.98) = 0.1041
d. None of the preceding
e. E(X) = 3.015, STDEV(X)= 0.0024; P (X ≤ 2.98) = 0.2941
f. E(X) = 2.413, STDEV(X)= 0.049, P (X ≤ 2.98) = 0.2941

b. E(X) = 3.015, STDEV(X)= 0.049, P (X ≤ 2.98) = 0.2941

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean of the uniform probability distribution is:

The standard deviation of the uniform distribution is:

The probability that we find a value X lower than x is given by the following formula.

Uniform distribution between 2.93 and 3.1 volts

This means that . So

Mean:

Standard deviation:

What is the probability that a battery has a voltage less than 2.98?

So the correct answer is:

b. E(X) = 3.015, STDEV(X)= 0.049, P (X ≤ 2.98) = 0.2941

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step-by-step explanation: