(7/2) to the negative second power

 4/49

(7/2)^(-2) = (2/7)^2

note how I took the reciprocal of the fraction to make the exponent positive. The rule is (a/b)^(-c) = (b/a)^c

Then we square each piece of the fraction 2/7 getting

(2/7)^2 = (2^2)/(7^2) = 4/49

4/49 is approximately equal to 0.08163265306122

A= r2 × 3.14 7x7 ↓ ↓ 49 × 3.14 = 153.86 → 153.9

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.