The diagram shows a right triangle and three squares. The area of the largest square is 67 units squared.

Which could be the areas of the smaller squares?
Choose all answers that apply:

(Choice A)
A
8 and 58
(Choice B)
7 and 60

(Choice C)

11 and 56
PS this is a Khan Academy question

B. 7 and 60

C. 11 and 56

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The area of the three squares must satisfy the Pythagorean Theorem

so

where

c^2 is the area of the largest square

a^2 and b^2 are the areas of the smaller squares

The sum of the areas of the smaller squares must be equal to 67

therefore

7 and 60 ----> could be the areas of the smaller squares (60+7=67)

11 and 56 ----> could be the areas of the smaller squares (11+56=67)

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°