A students says that the center of a circle with equation (x-2)^2 + (y+3)^2 is (-2,3). What is the student’s error?

Step-by-step explanation:

The center of the circle with equation (x-2)²+ (y+3)² is given by (2, -3).

So, the student made an error on writing the center

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.