You have a coin… and a die (six numbers)
a. COIN: heads or tails
b. DIE: six different numbers
How many unique outcomes are there, remember, you
are combining Outcomes of the coin and outcomes on the die?
So a result of HEADS & 6 are one outcome, HEADS & tails are another, etc. etc.

there will be 12 different outcomes

Step-by-step explanation:

There are 6 sides to the die and 2 sides to the coin. You multiply both of them and get 12

12 unique combinations

Step-by-step explanation:

6 x 2 = 12

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!