The equation d = 16t^2 gives the distance d in feet that a golf ball falls in t seconds. How many seconds will it take a golf ball to drop to the ground from a height of 4 feet? 64 feet?

0.5 seconds for 4 ft and 2 seconds for 64 ft

d=16t^2

4=16t^2

/16  /16

t^2=1/4

t=1/2

0.5 seconds for 4 ft

64 = 16t^2

/16    /16

4=x^2

x=2

2 seconds for 64 ft

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)