An unsaturated solution is made by completely dissolving 20.0 grams of nano3
in
100.0 grams of water at 20.0°c.
56 in the space in your answer booklet, show a correct numerical setup for calculating the
number of moles of nano3
(gram-formula mass = 85.0 grams per mole) used to make
this unsaturated solution. [1]
57 determine the minimum mass of nano3
that must be added to this unsaturated
solution to make a saturated solution at 20.0°c. [1]
58 identify one process that can be used to recover the nano3
from the unsaturated

The following are the answers to the questions presented:

a.       Mols =

b.      88g – 20g = 68g 

c.       Evaporation of water / Boiling of water

I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt