One side of a triangle is twice the shortest side. The third side is five feet more than the shortest side. The perimeter is 17 feet. Find the lengths of all three sides.

3, 6 and 8

Step-by-step explanation:

In order to solve the problem, we call:

= length of the 1st side of the triangle

= length of the 2nd side of the triangle

= length of the 3rd side of the triangle

From the text of the question, we know that:

- One side of a triangle is twice the shortest side --> we can write this as

(1) (assuming "a" is the shortest side)

- The third side is five feet more than the shortest side. -->

(2)

- The perimeter is 17 feet -->

(3)

So now we have 3 equations with 3 unknown variables. Substituting (1) and (2) into (3) we can find the value of "a", the shortest side:

And so

So the lengths of the 3 sides are 3, 6 and 8.

y=35

x=5

step-by-step explanation: