If x-5y=37 and x and y are positive integers, then what is the least possible value of x?
Please answer
Will give brainlist?

x=42

Step-by-step explanation:

Reading the equation tells us that

x has to quite a big number, because after subtracting 5y's we end up with 37.

Change the equation to

x=37+5y

The smallest positive integer which

y can be is 1, x=37+5(1)=42

choice b is correct

step-by-step explanation:

we have been given the following system of linear inequalities;

we are required to graphically determine the solution to these system of inequalities. using a graphing tool, the solution is as shown in the attachment below;

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.