In triangle JKL, the bisector of angle J divides KL into XK with length y + 3 and XL with length 2y. If JK = 12 and JL = 16, what is the length of XK? *

The length of XK = 12.7

Step-by-step explanation:

Given that

JK = 12 , JL = 16 , KX = y + 3  , XL = 2y

From the Δ JKX

 ----- (1)

From the Δ JXL

---------- (2)

From Equation (1) & (2) we get

144 - (

By solving above equation we get

y = 9.7

Therefore the length of XK = y + 3 = 9.7 + 3 = 12.7

so we may be on two differnt triangles since he didnt involve the picture like he shouldve but the answer is 9 in. ill show proof:

Step-by-step explanation:

40 minutes

step-by-step explanation:

add the time and multiply by 2

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )