The length of a rectangular garden is 2 feet more than twice it's width. If the area is 40 square feet, how much fencing would be needed to enclose the garden?

w =4 ft and l =10 ft

Step-by-step explanation:

Let w = width

l = 2w+2

A = l*w

A = (2w+2)(w)

 40  = (2w+2) w

Distribute

40 = 2w^2 +2w

Subtract 40

0 = 2w^2 +2w - 40

Dividing each side by 2

0 = w^2 +w -20

Factor

0 = (w+5) (w-4)

Using the zero product property

w+5 =0     w-4=0

w= -5  w=4

Since we cant have a negative length

w=4

l = 2w+2 = 2(4)+2 = 8+2 =10

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

(a) the volume of the cone is 20/3 in3

hence, option a is correct.