The cubic parent function y=x^3 contains the point (2,8). If the function reflected over the x-axis and shifted right 6 units, what are the coordinates of the new point

The new coordinate are (8,-8)

Step-by-step explanation:

Whenever a graph is reflected about the x-axis, positive y values become negative and vice versa. In this case positive y(8) becomes negative (-8). While the x values remain unchanged.

So the coordinates when moving by one unit will be (2,-8)

Shifting it 6units to the right increases the x values by six to give the new coordinates which is (8,-8)

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a