Consider this system of equations:
2/3x+3/5y=12 (equation a)
5/2y-3x=6 (equation b)
the expression that gives the value of x is:
the solution for the system of equations is:

To find the value of x, we have to eliminate y by making y the subject of formula in any of the equations.
Multiply equation A by 5/3 t.o get,
5/3(2/3x) + 5/3(3/5y) = 5/3(12)
10/9x + y = 20
y = 20 - 10/9x
substituting for y into equation b, we have:
5/2(20 - 10/9x) - 3x = 6
50 - 25/9x - 3x = 6
52/9x = 44
52x = 396
The expression that gives the value of x is: 52x = 396
Hence, x = 396/52 = 99/13
y = 20 - 10/9(99/13) = 20 - 110/13 = 150/13
The solution for the system of equations is: (99/13, 150/13)

12 rio aoice of q kqpd so r lagr