Find the solution(s) to the system of equations. y= x^2 -2x -3 y= x -3

two solutions : (0,-3)  , (3,0)

Step-by-step explanation:

hello :

y= x² -2x -3 ...(*)

y= x -3(**)

x²-2x-3 = x -3

x²-3x=0

x(x-3) = 0

x=0 or x-3=0

x=0 or x=3

but : y=x-3

1) x=0   y=0-3=-3

2) x=3   y=3-3=0

two solutions : (0,-3)  , (3,0)

where's the diagrams?

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!