A certain university has 8 vehicles available for use by faculty and staff. Six of these are vans and 2 are cars. On a particular day, only two requests for vehicles have been made. Suppose that the two vehicles to be assigned are chosen at random from the 8 vehicles available. (Enter your answers as fractions.)
a.) Let E denote the event that the first vehicle assigned is a van. What is P(E) ?
b.) Let F denote the probability that the second vehicle assigned is a van. What is P(F|E)?
c.) Use the results of parts(a) and (b) to calculate P(E and F)

a)

b)

c)

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

We have that:

8 vehicles, of which 6 are vans.

a.) Let E denote the event that the first vehicle assigned is a van. What is P(E) ?

8 vehicles, of which 6 are vans.

So

b.) Let F denote the probability that the second vehicle assigned is a van. What is P(F|E)?

P(F|E) is the probability that the second vehicle assigned is a van, given that the first one was.

In this case, there are 7 vehicles, of which 5 are vans. So

c.) Use the results of parts(a) and (b) to calculate P(E and F)

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300