What is the slope of the line through (3, 2) and (-3, 4)?

Slope =-1/3

Step-by-step explanation:

(3,2) x1 =3, y1=2

(-3,4) x2=-3, y2 =4

Slope=(y2-y1) /(x2-x1)

Slope=(4-2) /(-3-3)

Slope =2/(-6)

Slope=-1/3

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

answer: you need to organize this better it does not make sense.

step-by-step explanation: ?