If the radius of a circle is 15 units and the center
of the circle is (−3, 2), what is the equation of
the circle?
A. (x − 2)2 + (y + 3)2 = 30
B. (x + 2)2 + (y − 3)2 = 225
C. (x + 3)2 + (y − 2)2 = 225
D. (x − 3)2 + (y + 2)2 = 15
HELP ME PLEASE

For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)