If a projectile is fired straight upward from the ground with an initial speed of 96 feet per second, then its height h in feet after t seconds is given by the function h(t)= -16t^2 + 96t. Find the maximum height of the projectile.

144 feet

Step-by-step explanation:

The quadratic equation is:

The general form of a quadratic is  

So, we can match the equations and say:

a = -16

b = 96

c = 0

Now, for quadratic equations, the max value occurs at and the max value is what we get when we put that number in the function. First, lets find the value on which is occurs:

Now, put x = 3 into the equation:

The max height of projectile is 144 feet

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8

i believe that the answer is

b. y-1=-2(x-4)

hope this !