The solutions to the equation x4 + 2x3 + 24 = 13x2 + 14x occur at x = –4, x = –2, x = 1, and x = 3. At what points does the graph of the function f(x) = x4 + 2x3 – 13x2 – 14x + 24 intersect the x-axis?

A) (0, –4), (0, –2), (0, 1) and (0, 3)
B) (0, 4), (0, 2), (0, –1) and (0, –3)
C) (–4, 0), (–2, 0), (1, 0), and (3, 0)
D) (4. 0), (2, 0), (–1, 0), and (–3, 0)

C. (–4, 0), (–2, 0), (1, 0), and (3, 0).

Step-by-step explanation:

The points where the graph intersects the x axis have y coordinates of zero and the given x coordinates.

(–4, 0), (–2, 0), (1, 0), and (3, 0) is the answer.

answer: #1 ads up by 8 and i don't know #2

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)