A quarterback throws a football toward a receiver from a height of 6 ft. The initial vertical velocity of the ball is 14 ft/s. At the same time that the ball is thrown, the receiver raises his hands to a height of 8 ft and jumps up with an initial vertical velocity of 10 ft/s.

Projectile motion formula:

h = -16t2 + vt + h0

t = time, in seconds, since the ball was thrown

h = height, in feet, above the ground

{
Complete the system that models the heights of the ball and the receiver’s hands over time.

h = -16t² + 14t +
6
h = -16t² +
10
t
+
8

After
seconds, the receiver's hands and the ball will be at the same height.