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Mathematics, 03.04.2020 18:13, pryncesz2859
Let Bold v 1equals[Start 3 By 1 Matrix 1st Row 1st Column 0 2nd Row 1st Column 0 3rd Row 1st Column negative 3 EndMatrix ], Bold v 2equals[Start 3 By 1 Matrix 1st Row 1st Column 0 2nd Row 1st Column negative 3 3rd Row 1st Column 6 EndMatrix ], and Bold v 3equals[Start 3 By 1 Matrix 1st Row 1st Column 2 2nd Row 1st Column negative 5 3rd Row 1st Column 9 EndMatrix ]. Does StartSet Bold v 1 comma Bold v 2 comma Bold v 3 EndSet span set of real numbers R cubed? Why or why not? Choose the correct answer below. A. Yes. Any vector in set of real numbers R cubed except the zero vector can be written as a linear combination of these three vectors. B. No. The set of given vectors spans a plane in set of real numbers R cubed. Any of the three vectors can be written as a linear combination of the other two. C. No. When the given vectors are written as the columns of a matrix A, A has a pivot position in only two rows. D. Yes. When the given vectors are written as the columns of a matrix A, A has a pivot position in every row.
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Mathematics, 21.06.2019 22:00, juniorracer148
For [tex]f(x) = 4x + 1[/tex] and (x) = [tex]g(x)= x^{2} -5,[/tex] find [tex](\frac{g}{f}) (x)[/tex]a. [tex]\frac{x^{2} - 5 }{4x +1 },x[/tex] ≠ [tex]-\frac{1}{4}[/tex]b. x[tex]\frac{4 x +1 }{x^{2} - 5}, x[/tex] ≠ ± [tex]\sqrt[]{5}[/tex]c. [tex]\frac{4x +1}{x^{2} -5}[/tex]d.[tex]\frac{x^{2} -5 }{4x + 1}[/tex]
Answers: 2
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Let Bold v 1equals[Start 3 By 1 Matrix 1st Row 1st Column 0 2nd Row 1st Column 0 3rd Row 1st Column...
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