Two hamburgers and three cokes cost $10.50. Four hamburgers and four cokes cost $18.00. Find the cost of a hamburger and a coke.

hamburger $3.00

Coke $1.50

Step-by-step explanation:

2hamburgers & 3cokes= $10.50

4hamburgers & 4cokes= $18.00

Let hamburger represent H

And coke represent C

2H +3C= 10.50equation 1

4H+4C= 18.00equation 2

2H =10.50 -3Cequation 3

The 4H can be rewriting as

2(2H) right

So substitute for the 4H

So we have,

2(2H) +4C= 18

Substitute for 2H

2(10.50 -3C) +4C =18

Open the bracket

21 -6C +4C= 18

21-2C= 18

-2C = 18-21

-2C = -3

Minus cancel minus

C= 3/2 = $1.5

Substitute for c in equation 1

2H+3C =10.50

2H+3(1.5)= 10.50

2H+4.5=10.5

2H= 10.5-4.5

2H =6

H= 6/2

H=$3

So

An hamburger cost $3.00

A coke cost $1.50

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.

he answer is x=1x3 because x=1 to x=3