Acylindrical vase has a diameter of 6 inches. at the bottom of the vase, there are 6 marbles, each of diameter 2 inches. the vase is filled with water up to a height of 10 inches. what is the volume of water in the vase?
a.) 36π in^3
b.) 54π in^3
c.) 66π in^3
d.) 82π in^3

The volume of the water is determined by taking the difference between the volume of the water initially and the volume of the marbles placed in the cylinder/

Volume of water = Volume of water 10 inch high - Volume of 6 marbles 
= π(3 in)^2 * (10 in) - 6(4/3)(π)(1 in)^3 = 90π in^3 - 8π in^3 = 82π in^3