Eleven letters spelling "probability" are placed in a bag. You pick one, replace it, and then pick another. What is the probability of picking a P and then a I?

It is 2/121.

Step-by-step explanation:

For the first draw, the probability of picking P is 1/11 since there is only one P letter in the 11 letters. If we replace the P after drawing, then for the second draw, the probability of drawing I is 2/11 since there are 2 I's in the 11 letters.

Since the events are seperate, the probability of picking P and then picking I is (1/11)x(2/11) = 2/121.

I hope this answer helps.

the answer is 5636.7

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice