Awater storage tank has the shape of a cylinder with diameter 10 ft. it is mounted so that the circular cross-sections are vertical. if the depth of the water is 8 ft, what percentage of the total capacity is being used?

Let
l= length of the cylinder 

V=πr²l r=11 Vt=(380.133)l 
x=√(121-y²) 

dv=2x dy 
10 
V=∫2l√(121-y²) dy=(373.965)l ft³ 
-11 
% of the total capacity being used=(373.965/380.133)100 
=98.38%

The answer would be (c)

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to