In the x-y plane l has a y-intercept of -13 and is perpendicular to the line with equation y= -2/3x. If the point (10,b) is on the line l, what is the value of b?

Step-by-step explanation:

Here, the  equation of the line perpendicular to line l  is given as:

   ..... (1)

The y - intercept of l is given as: - 13

The point on l = (10,b)

Now, the equation of line with point (10,b) and y intercept as - 13 is given as:

y = m x + C  : (x,y) is point on line and C is y- intercept

So, the equation of line l is given as:

b =  m (10)  +  (-13)

or, b = 10 m - 13    .. (2)

As given (1) and (2) are perpendicular.

So, slope of line 1 x Slope of line l =  -1

Putting this value of m in (2), we get:

b = 10 m - 13  =  

or, b = 2

Hence, in the given point (10,b) the value of b = 2.

450 is the final answer! : )

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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