Solutions to this equation!!

w=3/5 or w=-5

Step-by-step explanation:

5w^2+22w=15

5w^2+22w-15=0 (quadratic equation)

a=5, b=22, c=-15

w1,2 =(-b+-sqrt(b^2-4ac))/2a

w1,2 =(-22+-sqrt(22^2-4*5*(-15))/2*5

w1,2 =(-22+-sqrt(484+300))/10

w1,2=(-22+-sqrt(784))/10

w1,2=(-22+-28)/10

w1=(-22+28)/10, w2=(-22-28)/10

w1=6/10, w2=-50/10

w1=3/5, w2=-5

ou would have 12 of each